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package ds.bst.leetcode450;
/**
* 删除二叉搜索树中的节点
* LeetCode 450 https://leetcode-cn.com/problems/delete-node-in-a-bst/
*
* @author yangyi 2020年12月05日16:11:25
*/
public class Solution {
public class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode() {
}
TreeNode(int val) {
this.val = val;
}
TreeNode(int val, TreeNode left, TreeNode right) {
this.val = val;
this.left = left;
this.right = right;
}
}
/**
* 5
* / \
* 3 6
* / \ \
* 2 4 7
*/
private TreeNode createTree() {
TreeNode node_5 = new TreeNode(5);
TreeNode node_3 = new TreeNode(3);
TreeNode node_6 = new TreeNode(6);
TreeNode node_2 = new TreeNode(2);
TreeNode node_4 = new TreeNode(4);
TreeNode node_7 = new TreeNode(7);
node_5.left = node_3;
node_5.right = node_6;
node_3.left = node_2;
node_3.right = node_4;
node_6.right = node_7;
return node_5;
}
private void inOrder(TreeNode root) {
if (root == null) {
return;
}
inOrder(root.left);
System.out.print(root.val + " ");
inOrder(root.right);
}
public TreeNode deleteNode(TreeNode root, int key) {
if (root == null) {
return null;
}
if (root.val > key) {
root.left = deleteNode(root.left, key);
} else if (root.val < key) {
root.right = deleteNode(root.right, key);
} else if (root.val == key) {
if (root.left == null) {
return root.right;
}
if (root.right == null) {
return root.left;
}
//右子树中找到最小值并上来
TreeNode min = getMin(root.right);
root.val = min.val;
//删除右子树中找出来的最小值
root.right = deleteNode(root.right, min.val);
}
return root;
}
private TreeNode getMin(TreeNode root) {
if (root == null) {
return null;
}
while (root.left != null) {
root = root.left;
}
return root;
}
public static void main(String[] args) {
Solution solution = new Solution();
System.out.println("构建一棵树");
TreeNode root = solution.createTree();
System.out.println("中序遍历构建好的树: ");
solution.inOrder(root);
System.out.println();
System.out.println("删除树中值为3的节点: ");
TreeNode result = solution.deleteNode(root, 3);
System.out.println("中序遍历删除对应的3节点之后剩余的树: ");
solution.inOrder(result);
}
}