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Error dividing Period by timedelta #382
Description
The following snippet fails for me (using Python 3.7.3).
It looks like pendulum is depending on a private method of timedelta (_to_microseconds), which does not exist in all versions:
> from datetime import timedelta
> from pendulum import datetime
> p = datetime(2019, 1, 1) - datetime(2019, 1, 1)
> d = timedelta(days=1)
> p/d---------------------------------------------------------------------------
AttributeError Traceback (most recent call last)
<ipython-input-33-79e6ca0b60d8> in <module>
----> 1 p/d
~/.virtualenvs/test/lib/python3.7/site-packages/pendulum/period.py in __truediv__(self, other)
325
326 def __truediv__(self, other):
--> 327 return self.as_interval().__truediv__(other)
328
329 __div__ = __floordiv__
~/.virtualenvs/test/lib/python3.7/site-packages/pendulum/duration.py in __truediv__(self, other)
357 usec = self._to_microseconds()
358 if isinstance(other, timedelta):
--> 359 return usec / other._to_microseconds()
360
361 # Removing years/months approximation
AttributeError: 'datetime.timedelta' object has no attribute '_to_microseconds'
Activity
The-Fonz commentedon Sep 16, 2020
I'm having this exact issue on Python 3.8.5 and Pendulum 2.1.2.
jacob-r-g commentedon Aug 19, 2021
I am having this same issue
AlexisBRENON commentedon Jul 2, 2024
Still facing this issue with Pendulum 3.0.0 and Python 3.11.
My current workaround is to manually convert division terms to seconds (I don't mind the microsecond parts).